I ask this because the tenons that were dropped from my test twd. (the one that Kenneth also ran) were 55% of .75". In other worlds, that means that the resulting tenon was .4125" thick. That would require a .4125" wide corresponding dado, if fit tolerances are set to zero, in the adjoining part recieving the dado would it not? If this is the case then why were my .25" long tenons dropped on my parts with a bit daimeter of .253"?
When I speak of tenon length I am referring to how far off the edge of the panel the tenon extends.
When I think of dado I think of a grove that is milled into the face of material by a DADO set on a table saw or a router bit in a router (or spindle).
I am assuming that what TWD meant by dado diameter is actually referring to the width of the dado.
Dado depth is usually determined by tenon length and vice versa in my way of thinking.
Boundary box is a term that I learned from the Thermwood shop to describe the pocket geometry outline that is used to create pocket cuts.
""It is not the tenon depth that dictates what tool is chosen for an operation. The tool is chosen based on the the dia. of the dado (tenon thickness). For example: if your dado is going to be .375, then a tool dia. that can cut this dia. within two passes is selected (tool setup for rout/dado with dia. .374 and smaller)." - TWD
Am I interpreting this statement as meaning that the tool chosen to mill out the pocket for the tenon shoulders (the boundary box) is determined by the dado diameter (guessing that means dado width since they refer to tenon thickness)?
If so then the question is still unanswered in my mind. Why didn't the .253" bit cut the shoulder if it can cut the .4125" wide dado for the same tenon?
Or does it make sense to try and understand it if you find out that .25" diameter works?
Is this considered fighting the program logic?