Indexer and ArtCam Pro 2008

[jim_vv]

Jack, My model width is the diameter of the part multiplied by 3.142. 3" x 3.142 = 9.426 (I actually went 9.44 because the Wrapped view showed a tiny unmachined fin). The material is 1/2 the diameter and Z zero is bottom of block. Zero the machine at top of your blank. Your orientation text on my simulation is correct except for the width text.
42881.jpg

[jim_vv]

I just noticed that my previous pictures show the material wrong. Can I edit a previous post? If not I will follow with revised screen shots. Sorry.

[jim_vv]

Guys, I am so sorry. I noticed that my 3D toolpath previews this morning's post show the material located in relation to the part incorrectly.

Here is the revised Z Rough


42886.jpg

Again, I apologize.


Here is the revised Machine Relief


42887.jpg

And the revised Feature Machining


42888.jpg

[myxpykalix]

Ok, so let me see if i understand...
"my model width is the diameter of the part multiplied by 3.142. 3" x 3.142 = 9.426

So using that equation of "pi" to calculate my "width" I first measure my diameter and make my width of the model the results of the equation like in your example above?

So using that in this example:
2.75" diameter X 3.142= 8.64" is this correct?

So the idea is you fit the model to the material?

So what if someone sent me a model that was 8.64"
(just using width in this example so as not to confuse) and i did not know I was starting with a 2.75" diameter piece. How can I take that 8.64" width and back figure what my diameter would be that i would have to cut my 3" square piece down to, to be able to have this fit?

This is one way i learn is by taking the example the teacher gives you, do your figuring, then have the teacher affirm that you are doing it correctly.
So teacher do i earn a gold star?

[jim_vv]

Jack, You get a gold star! Circumference equals Width or Height (depending on what axis your indexer is mounted parallel to). Think of it the way Stephen described how he does his. He does all of his work flat. I think he has a good technique!

[jim_stadtlander]

Jack,

8.64" Divided by "pi" 3.142 = 2.749.... Or a model 4.5 wide would then be for a turning 1.432 in dia.

[myxpykalix]

Jim,
"8.64" Divided by "pi" 3.142 = 2.749"
2.749 is close enough for me to 2.75 or good enough for government work, for sure!

".... Or a model 4.5 wide would then be for a turning 1.432 in dia."
I'm not sure i understand what you are saying here.
EDIT.i did the math...i get it..thanks!